# A tin box of length 9 metres, breadth 2 metres and height 50 cm is madewithout a lid. Find the total area of its faces. ​

A tin box of length 9 metres, breadth 2 metres and height 50 cm is made
without a lid. Find the total area of its faces. ​

### 2 thoughts on “A tin box of length 9 metres, breadth 2 metres and height 50 cm is made<br />without a lid. Find the total area of its faces. ​”

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$$\underline{\bf \blue {Given}}\begin{cases} & \sf{\bullet\:Length\:of\;tin\;box = \bf{9\;m}} \\ & \sf{\bullet\:Breadth\;of\;tin\;box = \bf{2\;m}} \\& \sf{\bullet\:Height\:of\:tin\:box = \bf{50\:cm}} \end{cases}\\$$

$$\underline{\bf \blue {To\:find\::}}$$

$$\sf Total \:surface\: area\: of\: tin \:box\:?$$

$$\underline{\bf \blue {Solution\::}}$$

◍ Changing height from cm to m :-

$$:\longrightarrow\qquad\sf Height_{(In\:m)}\:=\:\dfrac{50}{100}\:$$

$$:\longrightarrow\qquad\sf Height_{(In\:m)}\:=\:\dfrac{\cancel{50}}{\cancel{100}}\:$$

$$:\longrightarrow\qquad\sf Height_{(In\:m)}\:=\:\underline{\bf{0.5\:m}}\:$$

◍ Formula that we will use :-

$$\red\bigstar\:\boxed{\boxed{\sf \green{Total\:surface\:area_{(Cuboid)}\:=\:\bf{2(lb\:+\:bh\:+\:hl)}}}}$$

◍ Putting all values in the formula :-

$$:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:2(9\:\times\:2\:+\:2\:\times\:0.5\:+\:0.5\:\times\:9)$$

$$:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:2(18\:+\:1\:+\:4.5)$$

$$:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:2\:\times\:23.5$$

$$:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:47$$

$$\underline {\boxed {\frak {\therefore \pink {Total\:surface\:area_{(Tin\:box)}\:\leadsto\:47\:m^2}}}}\:\purple\bigstar$$

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Length of box L = 9 m

Breadth of box B = 2 m

Height of box H = 50 Cm = 0.5 m

total area = 2 (LB + BH + LH) – L * B

= 2 (9*2 + 2*0.5 + 9*0.5) – 9 * 2

= 2 (18 + 1 + 4.5) – 18

= 2 ( 23.5 ) – 18

= 47 – 18

= 29 m^2

Step-by-step explanation: