A tin box of length 9 metres, breadth 2 metres and height 50 cm is made
without a lid. Find the total area of its faces. ​

2 thoughts on “A tin box of length 9 metres, breadth 2 metres and height 50 cm is made<br />without a lid. Find the total area of its faces. ​”

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   [tex]\underline{\bf \blue {Given}}\begin{cases} & \sf{\bullet\:Length\:of\;tin\;box = \bf{9\;m}} \\ & \sf{\bullet\:Breadth\;of\;tin\;box = \bf{2\;m}} \\& \sf{\bullet\:Height\:of\:tin\:box = \bf{50\:cm}} \end{cases}\\ [/tex]

   [tex]\underline{\bf \blue {To\:find\::}}[/tex]

   [tex]\sf Total \:surface\: area\: of\: tin \:box\:?[/tex]

   [tex]\underline{\bf \blue {Solution\::}}[/tex]

   ◍ Changing height from cm to m :-

   [tex]:\longrightarrow\qquad\sf Height_{(In\:m)}\:=\:\dfrac{50}{100}\:[/tex]

   [tex]:\longrightarrow\qquad\sf Height_{(In\:m)}\:=\:\dfrac{\cancel{50}}{\cancel{100}}\:[/tex]

   [tex]:\longrightarrow\qquad\sf Height_{(In\:m)}\:=\:\underline{\bf{0.5\:m}}\:[/tex]

   ◍ Formula that we will use :-

   [tex]\red\bigstar\:\boxed{\boxed{\sf \green{Total\:surface\:area_{(Cuboid)}\:=\:\bf{2(lb\:+\:bh\:+\:hl)}}}}[/tex]

   ◍ Putting all values in the formula :-

   [tex]:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:2(9\:\times\:2\:+\:2\:\times\:0.5\:+\:0.5\:\times\:9)[/tex]

   [tex]:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:2(18\:+\:1\:+\:4.5)[/tex]

   [tex]:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:2\:\times\:23.5[/tex]

   [tex]:\implies\sf\:Total\:surface\:area_{(Tin\:box)}\:=\:47[/tex]

   [tex]\underline {\boxed {\frak {\therefore \pink {Total\:surface\:area_{(Tin\:box)}\:\leadsto\:47\:m^2}}}}\:\purple\bigstar[/tex]

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2. Answer:

   Length of box L = 9 m

   Breadth of box B = 2 m

   Height of box H = 50 Cm = 0.5 m

   total area = 2 (LB + BH + LH) – L * B

   = 2 (9*2 + 2*0.5 + 9*0.5) – 9 * 2

   = 2 (18 + 1 + 4.5) – 18

   = 2 ( 23.5 ) – 18

   = 47 – 18

   = 29 m^2

   Step-by-step explanation:

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