A stone is thrown vertically upward with a velocity of 25 m/s. How long does it take to reach the maximum height? also, calculate

2 thoughts on “A stone is thrown vertically upward with a velocity of 25 m/s. How long does it take to reach the maximum height? also, calculate”

1. Answer:

   Approximately 32 it is the correct answer

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2. Answer:

   v^2 -u^2 = 2gs

   here v = 0 m/s

   u= 25m/s

   g = -10m/s^2

   putting these value in equation,

   0^2 – 25^2 = 2× (-10)×s

   0 – 225 = -20s

   -225 = -20s

   s = -225/-20

   s = 11.25m

   height = 11.25 m

   Now, v= u + at

   0 = 25 + (-10)t

   -10t = -25

   t = 2.5second

   If this answer is correct please mark me as brainliest

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