# A square shaped park ABCD of side 110 m has two equalrectangular flower beds of size 15m x 7m. Length of the boundaryo

A square shaped park ABCD of side 110 m has two equal
rectangular flower beds of size 15m x 7m. Length of the boundary
of the remaining park is​

### 2 thoughts on “A square shaped park ABCD of side 110 m has two equal<br />rectangular flower beds of size 15m x 7m. Length of the boundary<br />o”

For Flower bed given that,

Length(l)=15 m

Width(w)=7 m

∴ Perimeter of flower bed =2×(l+b)

=2×(15+7)m

=44 m.

There are two such flower beds.

For each bed, its one length and one breadth lie on boundary of the park.

So, perimeter of both flower bed lying on park=

1/2 (2×primeter of one bed)

= 1/2 (2×44)=44 m

Now, side of square ABCD=110 m

Therefore, perimeter of ABCD=4×110 m=440 m

So, perimeter of remaining area of park=perimeter of ABCD-perimeter of both flower bed lying on park

=440−44=396 m

Step-by-step explanation:

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For Flower bed given that,

Length(l)=15 m

Width(w)=7 m

∴ Perimeter of flower bed =2×(l+b)

=2×(15+7)m

=44 m.

There are two such flower beds.

For each bed, its one length and one breadth lie on boundary of the park.

So, perimeter of both flower bed lying on park=

1/2 (2×primeter of one bed)

= 1/2 (2×44)=44 m

Now, side of square ABCD=110 m

Therefore, perimeter of ABCD=4×110 m=440 m

So, perimeter of remaining area of park=perimeter of ABCD-perimeter of both flower bed lying on park

=440−44=396 m

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