A square shaped park ABCD of side 110 m has two equal
rectangular flower beds of size 15m x 7m. Length of the boundary
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2 thoughts on “A square shaped park ABCD of side 110 m has two equal<br />rectangular flower beds of size 15m x 7m. Length of the boundary<br />o”

1. Answer:

   For Flower bed given that,

   Length(l)=15 m

   Width(w)=7 m

   ∴ Perimeter of flower bed =2×(l+b)

   =2×(15+7)m

   =44 m.

   There are two such flower beds.

   For each bed, its one length and one breadth lie on boundary of the park.

   So, perimeter of both flower bed lying on park=

   1/2 (2×primeter of one bed)

   = 1/2 (2×44)=44 m

   Now, side of square ABCD=110 m

   Therefore, perimeter of ABCD=4×110 m=440 m

   So, perimeter of remaining area of park=perimeter of ABCD-perimeter of both flower bed lying on park

   =440−44=396 m

   Step-by-step explanation:

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2. Answer:

   [tex] \huge \underline \mathfrak \pink{Hey 🙂 \: Answer \: }[/tex]

   For Flower bed given that,

   Length(l)=15 m

   Width(w)=7 m

   ∴ Perimeter of flower bed =2×(l+b)

   =2×(15+7)m

   =44 m.

   There are two such flower beds.

   For each bed, its one length and one breadth lie on boundary of the park.

   So, perimeter of both flower bed lying on park=

   1/2 (2×primeter of one bed)

   = 1/2 (2×44)=44 m

   Now, side of square ABCD=110 m

   Therefore, perimeter of ABCD=4×110 m=440 m

   So, perimeter of remaining area of park=perimeter of ABCD-perimeter of both flower bed lying on park

   =440−44=396 m

   [tex]\huge\colorbox{orange}{RîYàÑsH5➜❤️}[/tex]

   Reply