A square shaped park ABCD of side 110 m has two equalrectangular flower beds of size 15m x 7m. Length of the boundaryof the remaining park is About the author Adalynn

Answer: For Flower bed given that, Length(l)=15 m Width(w)=7 m ∴ Perimeter of flower bed =2×(l+b) =2×(15+7)m =44 m. There are two such flower beds. For each bed, its one length and one breadth lie on boundary of the park. So, perimeter of both flower bed lying on park= 1/2 (2×primeter of one bed) = 1/2 (2×44)=44 m Now, side of square ABCD=110 m Therefore, perimeter of ABCD=4×110 m=440 m So, perimeter of remaining area of park=perimeter of ABCD-perimeter of both flower bed lying on park =440−44=396 m Step-by-step explanation: [tex]thanks[/tex] ❤ Reply

Answer: [tex] \huge \underline \mathfrak \pink{Hey 🙂 \: Answer \: }[/tex] For Flower bed given that, Length(l)=15 m Width(w)=7 m ∴ Perimeter of flower bed =2×(l+b) =2×(15+7)m =44 m. There are two such flower beds. For each bed, its one length and one breadth lie on boundary of the park. So, perimeter of both flower bed lying on park= 1/2 (2×primeter of one bed) = 1/2 (2×44)=44 m Now, side of square ABCD=110 m Therefore, perimeter of ABCD=4×110 m=440 m So, perimeter of remaining area of park=perimeter of ABCD-perimeter of both flower bed lying on park =440−44=396 m [tex]\huge\colorbox{orange}{RîYàÑsH5➜❤️}[/tex] Reply

Answer:For Flower bed given that,

Length(l)=15 m

Width(w)=7 m

∴ Perimeter of flower bed =2×(l+b)

=2×(15+7)m

=44 m.

There are two such flower beds.

For each bed, its one length and one breadth lie on boundary of the park.

So, perimeter of both flower bed lying on park=

1/2 (2×primeter of one bed)

= 1/2 (2×44)=44 m

Now, side of square ABCD=110 m

Therefore, perimeter of ABCD=4×110 m=440 m

So, perimeter of remaining area of park=perimeter of ABCD-perimeter of both flower bed lying on park

=440−44=396 m

Step-by-step explanation:[tex]thanks[/tex]

❤

Answer:[tex] \huge \underline \mathfrak \pink{Hey 🙂 \: Answer \: }[/tex]

For Flower bed given that,

Length(l)=15 m

Width(w)=7 m

∴ Perimeter of flower bed =2×(l+b)

=2×(15+7)m

=44 m.

There are two such flower beds.

For each bed, its one length and one breadth lie on boundary of the park.

So, perimeter of both flower bed lying on park=

1/2 (2×primeter of one bed)

= 1/2 (2×44)=44 m

Now, side of square ABCD=110 m

Therefore, perimeter of ABCD=4×110 m=440 m

So, perimeter of remaining area of park=perimeter of ABCD-perimeter of both flower bed lying on park

=440−44=396 m

[tex]\huge\colorbox{orange}{RîYàÑsH5➜❤️}[/tex]