A spherical solid ball of radius 8 mm is to be divided into eight equal parts by cutting it four times longitudinally along the same axis. Find the surface area of each of the final pieces thus obtained (in mm^2) ? (where pi= 22/7)
A spherical solid ball of radius 8 mm is to be divided into eight equal parts by cutting it four times longitudinally along the same axis. Find the surface area of each of the final pieces thus obtained (in mm^2) ?(where pi= 22/7)
✩ Required Solution:
➸ Having one curved surface and two plane surfaces in each identical part ,
➸ Angle between the plane surfaces is 45°
✰ Value given to us :
➸ Radio of ball (r) = 8mm
✩ According to question :
➸ Total surface area of one part = (1/8) of curved surface area of sphere + 2×Area of semi-circle.
EXPLANATION.
Spherical solid ball of radius = 8 mm.
It is divided into 8 equal parts by cutting it 4 times longitudinally.
As we know that,
Surface area of each pieces = TSA/8 + Area of circle.
As we know that,
Formula of :
Total surface area = 4πr².
Area of circle = πr².
Surface area of each pieces = 4πr²/8 + πr².
Surface area of each pieces = πr²/2 + πr².
Surface area of each pieces = πr² + 2πr²/2.
Surface area of each pieces = 3πr²/2.
Put the value in the equation, we get.
Surface area of each pieces = 3/2 x (22/7) x 8 x 8.
Surface area of each pieces = 4224/14.
Surface area of each pieces = 301.71 mm².
✩ Correct Question :
✩ Required Solution:
✰ Value given to us :
✩ According to question :
✩ Putting. r = 8
➸ ✰ 301.7 mm² (Answer ) ✰
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