A right-angled triangle ABC is such that: AB = 3.5 cm, BC = 2.3 cm and ∠B = 90° Find ∠C correct to one decimal place. About the author Cora
Answer:
AC^2 = AB^2 + BC^2
=(3.5)^2 + (2.3)^2
=12.25 + 5.29
=17.54