A rectangular Park is 300 metre long and 200 metre wide. There is a fountain in the center with the radius of 2 m . there are four

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1. Step-by-step explanation:

   Question:–

   A rectangular park is 300m long and 200m wide. There is a fountain in the center with the radius of 2m. There are also four flower beds with dimensions of 75cm × 50cm. Remaining area is the lawn. Find the area of the lawn.

   Answer:–

   Given :–

   • The given figures are five rectangle and a circle

   • Dimension of park – 300m long & 200m wide

   • Radius of fountain (circle) – 2m

   • Dimension of flower bed – 75cm × 50cm

   To find :–

   Area of the lawn (remaining area)

   Process :–

   Area of the park:–

   [tex]⇒Area \: of \: rectangle = Length × Breadth \\ \\ ⇒Area \: = (300×200)m \\ \\ ⇒50,000m²[/tex]

   Area of the Fountain:–

   [tex]⇒Area \: of \: circle = \pi \: {r}^{2} \\ \\ ⇒Area = 3.15 × (2)² \\ \\ ⇒Area = 3.15 × 2 × 2 \\ \\ ⇒Area = 12.6m²[/tex]

   Area of the flower bed:–

   [tex]⇒Area \: of \: rectangle = Length × Breadth \\ \\ ⇒Area = (0.75×0.5)m \\ \\ ⇒Area = 0.375 {m}^{2} \\ \\ = Total \: area \: of \: 4 \: beds = 0.375×4 = 1.5 {m}^{2} [/tex]

   Area of both flower bed and fountain:–

   [tex]⇒Area \: of \: commodities = Area \: of \: fountain + Area \: of \: flower \: beds \\ \\ ⇒Area \: of \: commodities = 12.6 {m}^{2} + 1.5 {m}^{2} \\ \\ ⇒Area \: of \: commodities = 14.1 {m}^{2} [/tex]

   Area of remaining lawn:–

   [tex]⇒Area \: of \: lawn = Area \: of \:total \: park \: – Area \: of \: all \: commodities \\ \\ ⇒Area \: of \: lawn = (50000-14.1)m² \\ \\ ⇒Area \: of \: lawn = 49985.9 {m}^{2} [/tex]

   The area of the lawn will be 49985.9m².

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   Hope it helps you…

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