a polynomial whose zeroes are reciprocal of zeroes of 2x²- x – 6

2 thoughts on “a polynomial whose zeroes are reciprocal of zeroes of 2x²- x – 6”

1. Answer:

   HOPE IT HELPS

   Step-by-step explanation:

   Answer:6x²+3x-2=0

   Step-by-step explanation:

   let the solution of x²+3x-6=0 equation is A and B

   so as we know

   A+B = -3/2

   and AB =-6/2= -3

   we have to find equation of reciprocal of zeros.

   so the zeros of that equation is 1/A and 1/B

   so \begin{gathered}\frac{1}{A}+\frac{1}{B}=\frac{A+B}{AB}\\\\= \frac{\frac{-3}{2}}{-3}\\\\=\frac{1}{2}[tex] < /p > < p > and [tex]\frac{1}{AB}=\frac{1}{-3}\end{gathered}

   A

   1

   +

   B

   1

   =

   AB

   A+B

   =

   −3

   2

   −3

   =

   2

   1

   [tex]</p><p>and[tex]

   AB

   1

   =

   −3

   1

   so formed equation is

   x²+(1/2)x+(-1/3)=0

   ⇒6x²+3x-2=0

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2. Step-by-step explanation:

   a polynomial whose zeroes are reciprocal of zeroes of 2x²- x – 6 -> 0

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