A pole broke at a point but did not separate, its top touched the ground at a distance of 7m from it’s

base. If the po

2 thoughts on “A pole broke at a point but did not separate, its top touched the ground at a distance of 7m from it’s <br /><br />base. If the po”

1. Distance between the pole and the

   ground = 7m

   Distance between the ground and the point at

   the pole where it broke= 24m

   Let the distance between the point at which the

   pole broke and the point where it touched the

   ground be “X”

   By, Pythagoras Theorem:

   X^2 = 7^2 + 24^2

   X^2 = 49 + 576

   X^2 = 625

   X = √625

   X = 25

   Therefore, the height of the pole

   = (X + 24)m

   = (25+24)m

   = 49m

   Hope you found it helpful!

   Reply

2. Answer:

   The total height of the pole is 49m

   Step-by-step explanation:

   • let AB be the height of remaining part of the broken pole = 24 m

   • BC be the distance from the base of the pole to the point where the top of the pole touches the ground = 7m

   • AC be the broken part of the pole

   ACB forms a triangle ️

   By phythagorus theorem

   AC² = AB² + BC²

   = (24)² + (7)²

   = 576 + 49

   AC² = 625

   (squaring on both sides)

   AC = 25

   Therefore the total height of the pole

   = AC + AB

   = 24+25

   = 49 m

   Hope this helps…!

   Reply