a mountain is an height of 8850m its base is at an elevation of 5450m . the temperature at the base is – 6° C if the temperature here drops at the rate of 1°C per 100m find the temperature at the top
The difference of the top of the mountain and the base. 8850-5450=3400.
The temperature drops 1 degrees Celsius per 100 meter. So, we divide it with the difference i.e 3400/100 =34. Then, the value gets – 34 degrees Celsius because it is gets dropped. – 34+-6=-40degree ccelsiu
Answer:
-40 degree celsius
Step-by-step explanation:
The difference of the top of the mountain and the base. 8850m-5450m=3400m
The temperature drops 1 degree Celsius per 100 meter ascent,
Hence we will divide it with the difference i.e 3400/100 =34.
Then, the value we get is – 34 degrees Celsius because it is gets dropped, -6 degree celcius is the to temperature at the base of the mountain
then,
– 34+-6=-40degree celsius
The answer is – 40degree celsius
Step-by-step explanation:
The difference of the top of the mountain and the base. 8850-5450=3400.
The temperature drops 1 degrees Celsius per 100 meter. So, we divide it with the difference i.e 3400/100 =34. Then, the value gets – 34 degrees Celsius because it is gets dropped. – 34+-6=-40degree ccelsiu
The answer is – 40degree celsius