A milk tank is in the form of frustum of a cone of height 3m with diameter of its upper& lower ends as 20m,12m respectively, find the cost of milk. which can fill the tank completely at rate of rs 25 per liter

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Answer:volume of a cone=22/7×10×6×3/3. m³=1320/7 m³=188.6 m³=188600 L

per liter milk costs=25 ruppes

188600 L milk costs=188600×25 ruppes=4715000 ruppes

Answer:230

Step-by-step explanation:given,

h=16cm,r=20cm,r=8cm

volume of frustum = πh/3(R²+r²+Rr)cm³

volume of frustum=π(16)/3((20)²+8²+(20)(8))cm³

8²+(20)(8))cm³

10459.428cm³=10.459 l

the cost of milk per litre = rs.22

10.459l=22×10.459=rs.230.10