A ladder 13 metres long stands at one side of a path, its top touching a wall on
the other side of the path at a height of 12

2 thoughts on “A ladder 13 metres long stands at one side of a path, its top touching a wall on<br />the other side of the path at a height of 12”

1. Answer:

   base is 5 m hope it helps you

   Step-by-step explanation:

   according to the question we know it is a right angle triangle

   Here,

   perpendicular Height = 12m

   Hypotenuse = 13m

   Base = ?

   So, by Pythagoras theorem

   [tex]Hypotenuse^{2} = height^2 + base^2\\13^2 = 12^2 + base^2\\169 = 144 + base^2\\169-144 = base^2\\25 = base^2\\5 = base[/tex]

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2. Answer:

   Step-by-step explanation:

   Length of ladder =13 m.

   BC=12m,AC=13 m.

   In ΔABC,

   AB

   2

   +BC

   2

   =C

   2

   (Pythagoras theorem)

   AB

   2

   =AC

   2

   −BC

   2

   =13

   2

   −12

   2

   =169−144

   =25

   ∴AB=5 m.

   ∴ The distance of the foot of the ladder from the base of the wall =5 m

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