A garden roller whose length is 3 m long and whose diameter is 2.8 m is rolled to level a garden. How much area will it cover in 8

A garden roller whose length is 3 m long and whose diameter is 2.8 m is rolled to level a garden. How much area will it cover in 8 revolutions?

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  1. Answer:

    Given :

    A garden roller whose length is 3 m long and whose diameter is 2.8 m is rolled to level a garden

    To Find :

    How much area will it cover in 8 revolutions?

    Solution :

    We know that

    CSA = 2πrh

    CSA = 2 × 22/7 × 2.8/2 × 3

    CSA = 44/7 × 1.4 × 3

    CSA = 44 × 0.2 × 3

    CSA = 44 × 0.6

    CSA = 26.4 m²

    Now

    Area covered = 8 × 26.4

    Area covered = 211.20 m²

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  2. Answer:

    • A garden roller will cover 211.2 m² of area in 8 revolutions.

    Step-by-step explanation:

    Given that:

    • A garden roller whose length is 3 m long and whose diameter is 2.8 m is rolled to level a garden.

    To Find:

    • How much area will it cover in 8 revolutions?

    Formula used:

    • CSA of cylinder = 2πRh

    Where,

    • CSA = Area covered by roller in one revolution
    • R = Radius of roller = 2.8/2 = 1.4 m
    • h = Length of roller = 3 m

    Finding the area covered by roller in one revolution:

    ⟶ CSA = 2 × 22/7 × 1.4 × 3

    ⟶ CSA = (2 × 22 × 1.4 × 3)/7

    ⟶ CSA = 184.8/7

    ⟶ CSA = 26.4

    ∴ Area covered by roller in one revolution = 26.4 m²

    Finding the area covered by roller in 8 revolutions:

    • One revolution = 26.4 m²
    • 8 revolutions = (8 × 26.4) = 211.2 m²

    Hence,

    • Area covered by roller in 8 revolutions = 211.2 m²
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