A farmer borrowed Rs. 25,000 from a sahakari bank at 3 p.c.p.a. What amount he will pay to the bank at the end of the year? *

2 points

Rs. 27570

Rs. 25750

Rs. 25570

Rs. 27750

# A farmer borrowed Rs. 25,000 from a sahakari bank at 3 p.c.p.a. What amount he will pay to the bank at the end of the year? *

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Solution:-━━━━━━━━━━━━━━━━━━━━━━━━━━

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◍ Here, the question has given us the principal, rate of interest and time that is Rs. 25,000, 3% per annum and for 1 year respectively. Now, the question has asked us to find the amount he will pay back. So to get the answer we need to apply the formula of simple interest first. And after it follow the steps given below.

ANSWER:-◈ The Simple Interest is Rs. 750.◈ The amount he will pay back is Rs. 25,750.GIVEN:-☆ Principal = Rs. 25,000

☆ Rate of Interest = 3% per annum

☆ Time = 1 year

TO FIND:-↠Amount he will pay back = ?

FORMULA:-⬤ Simple Interest = P × R × T / 100

⬤ Amount he will pay back = SI + Principal

SOLVING BY APPLYING THE FORMULA:-⇨ Principal = Rs. 25,000

⇨ Rate = 3%

⇨ Time = 1 year

⬤ Simple Interest = P × R × T / 100

FindingtheSI:–➢ Simple Interest = 25,000 × 3 × 1 / 100

➢ Simple Interest = 25,000 × 3 / 100

➢ Cancelling the zeros.

➢ Simple Interest = 250 × 3 / 1

➢ Simple Interest = 250 × 3

➢ Simple Interest = 250 × 3 = 750

➢ Simple Interest = Rs. 750

Thus,theSIisRs.750.⇨ Amount = Principal + Simple Interest

➢ Amount = 25,000 + 750

➢ Amount = 25,000 + 750 = 25,750

➢ Amount = Rs. 25,750

Hence, we got the answer. TheAmountis Rs.25,750.━━━━━━━━━━━━━━━━━━━━━━━━━━

Step-by-step explanation:P=25000r=3%t=1yearSI=p×r×t/100=25000×3×1/100=250×3=750Amount=SI+P=750+25000=25750