a cricketer scores the following runs in 5 innings : 43 , 88 , 23 , 56 , 11 . find the mean score About the author Eloise
Solution!! The concept of mean has to be used here. The observations and the number of observation are given. We have to find the mean of the observations. Observations → 43, 88, 23, 56, 11 Total number of observations = 5 The given information is sufficient to find the mean. Let’s do it!! Mean = Sum of observations ÷ Number of observations Mean = (43 + 88 + 23 + 56 + 11) ÷ 5 Mean = 221 ÷ 5 Mean = 44.2 Hence, the mean score of the cricketer is 44.2!! More information:- If you’re asked to find the median, then there are 2 different formulae. Median of odd number of observations = [(n + 1)/2]th term Median of even number of observations = [(n/2)th term + ((n/2) + 1)th term] ÷ 2 Reply
Answer:
sum of all observations /number of observations
43+88+23+56+11/5=44.2
Solution!!
The concept of mean has to be used here. The observations and the number of observation are given. We have to find the mean of the observations.
Observations → 43, 88, 23, 56, 11
Total number of observations = 5
The given information is sufficient to find the mean. Let’s do it!!
Mean = Sum of observations ÷ Number of observations
Mean = (43 + 88 + 23 + 56 + 11) ÷ 5
Mean = 221 ÷ 5
Mean = 44.2
Hence, the mean score of the cricketer is 44.2!!
More information:-
If you’re asked to find the median, then there are 2 different formulae.
Median of odd number of observations = [(n + 1)/2]th term
Median of even number of observations = [(n/2)th term + ((n/2) + 1)th term] ÷ 2