A committee of five will be chosen from 3 referees, 4 umpires and 6 scorers. What is the probability that there will be at least 3 scorers in the committee? About the author Maria

Answer : 5 member committee make out of 3 referees+ 4 umpires+ 6 scorers = 13 member # total selection = 13c5 = 1287 at least 3 scorer (x = 3,4,5) valid case 1 = 3 scorer + 2 (referee+umpire) case 2 = 4 scorer + 1 ( referee / umpire) caee 3 = all 5 scorer = 6c3×7c2 + 6c2×7c1 + 6c5 = 420 + 105 + 6 = 531 Answer = 531/1287 Please like this correct ans.. Reply

## Answer :

# total selection = 13c5 = 1287

at least 3 scorer (x = 3,4,5) valid

case 1 = 3 scorer + 2 (referee+umpire)

case 2 = 4 scorer + 1 ( referee / umpire)

caee 3 = all 5 scorer

= 6c3×7c2 + 6c2×7c1 + 6c5

= 420 + 105 + 6

= 531

## Answer = 531/1287

## Please like this correct ans..