A car travels 30 km at a uniform speed of 40 km/hr and the next 20km at a uniform speed of 20km/hr find its average speed. About the author Quinn
:::♧SOLUTION:– The total time for the journey is given as, t=v1d1+v2d2 =4030+2030 =2.25hour The average speed is given as vavg=td1+d2 =2.2530+30 =26.67km/h Ans: Thus, the average speed of the car is 26.67km/h. Answer by [tex]\huge\fbox\blue{@Shivu}[/tex] Reply
[tex]\sf t1 = \frac{s1}{v1} = \frac{10}{20} = \frac{1}{2}[/tex] [tex]\sf t2 = \frac{20}{10} [/tex] [tex]\rm avg \: speed = \frac{total \: distance}{total \: time}[/tex] [tex] \begin{gathered}\sf avg \: speed = \frac{30}{ \frac{1}{2} + 2 } \\\sf avg \: speed = \frac{30}{ \frac{5}{2} } \\\sf avg \: speed = \frac{30 \times 2}{5} \\\sf avg \: speed = 12 \frac{m}{s} \end{gathered} [/tex] I hope this helps ( ╹▽╹ ) Reply
:::♧SOLUTION:–
The total time for the journey is given as,
t=v1d1+v2d2
=4030+2030
=2.25hour
The average speed is given as
vavg=td1+d2
=2.2530+30
=26.67km/h
Ans: Thus, the average speed of the car is 26.67km/h.
Answer by [tex]\huge\fbox\blue{@Shivu}[/tex]
[tex]\sf t1 = \frac{s1}{v1} = \frac{10}{20} = \frac{1}{2}[/tex]
[tex]\sf t2 = \frac{20}{10} [/tex]
[tex]\rm avg \: speed = \frac{total \: distance}{total \: time}[/tex]
[tex] \begin{gathered}\sf avg \: speed = \frac{30}{ \frac{1}{2} + 2 } \\\sf avg \: speed = \frac{30}{ \frac{5}{2} } \\\sf avg \: speed = \frac{30 \times 2}{5} \\\sf avg \: speed = 12 \frac{m}{s} \end{gathered} [/tex]