a builder uses2_5 of available lands for road and park 3_8for the community hall and rest in construction of apartments whi

1 thought on “a builder uses2_5 of available lands for road and park 3_8for the community hall and rest in construction of apartments whi”

1. Answer:

   Road and park

   Step-by-step explanation:

   Lets make all the fractions have a common denominator first (40)

   Road and park = 2_5 = 16_40

   Community hall = 3_8 = 15_40

   Apartments = 40-(16+15)= 9_40

   Road and park is the largest, therefore it gets the maximum portion of the land

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