A boy is flying a kite with a string of length 100 m . If the string is tight and the angle of elevation of the kite is 26° 32′ ,

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A boy is flying a kite with a string of length 100 m . If the string is tight and the angle of elevation of the kite is 26° 32′ , find the height of the kite correct to one decimal place ( ignore the height of the boy ) .​

2 thoughts on “A boy is flying a kite with a string of length 100 m . If the string is tight and the angle of elevation of the kite is 26° 32′ ,”

  2. Answer:–

    • the height of kite is 44.7m

    To Find:–

    • the height of the kite correct to one decimal place.

    Given:–

    • Angle of elevation of the kite = 26° 32′

    • lenght of string = 100m

    Consider:–

    • AB as the height of the kite A and AC as the string,

    • → AC = 100
    • → Take AB = x

    In right triangle ABC

    • => Sin∅ = [tex]\frac{AB}{AC}[/tex]

    [tex] \:\:\:Substituting\:the\:values,[/tex]

    • ⇒sin26° 32′ = [tex]\frac{x}{100}[/tex]
    • ⇒0.4467 = [tex]\frac{x}{100}[/tex]
    • ⇒x = 100 × 0.4467
    • ⇒x = 44.67 ≈ 44.7m

    Hence, the height of the kite is 44.7 m.

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