A body moving with uniform velocity 5u is subject to uniform retardation a. It returns to thestarting point after(W) Su/a sec(6) 10u/a sec(20u/a sec(d) 10a/u sec About the author Kaylee
Step-by-step explanation: I. By III equation of motion, v 2 =u 2 +2as (5v) 2 =u 2 +2as 25v 2 −u 2 =2as 24u 2 =s 2a ∴ Distance travelled =S= a 12u 2 II. v 2 =u 2 +2as v 2 =(5u) 2 +2(−a)( a 12v 2 ) v 2 =25v 2 −24u 2 v 2 =u 2 v=1u ⇒v=−u. please mark me brainliest Reply
Step-by-step explanation:
I. By III equation of motion,
v
2
=u
2
+2as
(5v)
2
=u
2
+2as
25v
2
−u
2
=2as
24u
2
=s
2a
∴ Distance travelled =S=
a
12u
2
II. v
2
=u
2
+2as
v
2
=(5u)
2
+2(−a)(
a
12v
2
)
v
2
=25v
2
−24u
2
v
2
=u
2
v=1u
⇒v=−u.
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Answer:
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