A body floats 2/9 of its volume above the surface what is the ratio of the body submerged volume to its exposed volume !! please a

2 thoughts on “A body floats 2/9 of its volume above the surface what is the ratio of the body submerged volume to its exposed volume !! please a”

1. Answer:

   I don’t know

   Step-by-step explanation:

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2. Answer:

   here is your answer…

   if 2/9th of the volume of the body floats above the surface, then this is the exposed volume..

   then, the submerged volume is 9/9 – 2/9 , as the remaining will be inside the surface.

   which is 7/9..

   now coming to the ratio.. ratio is just the division of two numbers.

   p/q is the way of representing rational numbers… this format could also be used to represent ratio.

   we have to find the ratio of submerged volume to it’s exposed volume.

   submerged is 7/9 , where as exposed is 2/9..

   now, we will just have to divide the answers…

   which is

   7/9 ÷ 2/9

   this will be

   7/9 × 9/2

   9 will be cancelled out..

   7/2

   this is the ratio…

   7:2

   Step-by-step explanation:

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