A blacksmith have big iron ball of diameter
36cm. He first formed four identical
cylindrical rod out of this ball for some
construction work. When he finished his
work with the cylindrical rod, he again
mixed all the iron rod and formed some
identical small balls, each of radius 9cm.
Answer:
Step-by-step explanation:
Given :-
To Find :-
Solution :-
Let us assume that, n number of small ball formed by blacksmith.
so,
→ Volume of iron ball = n * volume of each small ball .
→ (4/3) * π * (R)³ = n * (4/3) * π (r)³
(4/3) and π will be cancel from both sides,
→ (R)³ = n * (r)³
→ (36/2)³ = n * (9)³
→ (18)³ = n * (9)³
→ 18 * 18 * 18 = n * 9 * 9 * 9
→ n = 2 * 2 * 2
→ n = 8 (Ans.)
Hence, the number of small ball formed by blacksmith are 8 .
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