A bag has 4 red balls and 2 yellow balls the balls are identical in all respects other the colour. A ball is drawn from the bag without looking into the bag. What in probability of getting a red ball? Is it more or less than geting a yellow ball? About the author Rylee
Answer: Correct option is B 3 2 Probability of an event P(E)= TotalNo.ofOutcomes No.ofFavourableOutcomes Here, Favourable Outcomes = Getting a Red ball Number of Favourable Outcomes = Number of Red Balls =4 Total Number of Outcomes =6 = Total Number of Balls ⇒P(E)= 6 4 = 3 2 Reply
Answer: Step-by-step explanation: Probability of an event P(E)= TotalNo.ofOutcomes _____________________ No.ofFavourableOutcomes Here, Favourable Outcomes = Getting a Red ball Number of Favourable Outcomes = Number of Red Balls =4 Total Number of Outcomes =6 = Total Number of Balls PE = [tex]\frac{4}{6} = \frac{2}{3}[/tex] Reply
Answer:
Correct option is
B
3
2
Probability of an event P(E)=
TotalNo.ofOutcomes
No.ofFavourableOutcomes
Here,
Favourable Outcomes = Getting a Red ball
Number of Favourable Outcomes = Number of Red Balls =4
Total Number of Outcomes =6 = Total Number of Balls
⇒P(E)=
6
4
=
3
2
Answer:
Step-by-step explanation:
Probability of an event P(E)= TotalNo.ofOutcomes
_____________________
No.ofFavourableOutcomes
Here,
Favourable Outcomes = Getting a Red ball
Number of Favourable Outcomes = Number of Red Balls =4
Total Number of Outcomes =6 = Total Number of Balls
PE = [tex]\frac{4}{6} = \frac{2}{3}[/tex]