A bag contains 6 red ball’s and 5 blue balls one ball is drawn of random from the bag what is the probability of getting a blue ball About the author Remi

Answer: Given:– A bag contains 6 red ball’s and 5 blue ball’s one ball is drawn of random from the bag, what is the probability of getting a blue ball. To Find:– Probability of getting a blue ball. Note:– ●》Probability = [tex] \frac{Number \ \ of \ \ favourable \ \ outcomes}{Total \ \ Number \ \ of \ \ outcomes} [/tex] ●》Here, Number of favourable outcomes is the bag contain balls for which ball we are finding, Total number of outcomes is total number of balls. Solution:– [tex] \huge\red{First, calculating \ \ missing \ \ values} [/tex] • Here, Number of favourable outcomes = 5 balls; Total number of outcomes = ? ☆ According to note second point~ ▪︎[tex] Total \ \ number \ \ of \ \ outcomes = Total \ \ number \ \ of \ \ balls ( red + blue \ \ balls ) [/tex] ▪︎[tex] Total \ \ number \ \ of \ \ outcomes = 5 + 6 \ \ balls [/tex] ▪︎[tex] Total \ \ number \ \ of \ \ outcomes = 11 \ \ balls [/tex] [tex] \huge\green{Total \ \ number \ \ of \ \ outcomes = 11 \ \ balls} [/tex] ______________________________________________ [tex] \huge\red{ Now, we \ \ will \ \ calculate \ \ Probability } [/tex] • Number of favourable outcomes = 5 balls, Total number of outcomes = 11 balls, Probability = ? ☆ According to note first point~ ▪︎[tex] Probability = \frac{Number \ \ of \ \ favourable \ \ outcomes}{Total \ \ number \ \ of \ \ outcomes} [/tex] ▪︎[tex] Probability = \frac{5 \ \ balls}{11 \ \ balls} [/tex] ☆ Here, calculations can’t be done so simply leave it and balls-balls will be canceled~ ▪︎[tex] Probability = \frac{5}{11} [/tex] [tex] \huge\green{Probability = \frac{5}{11}} [/tex] Answer:– Hence, the Probability of getting blue ball is = [tex] \frac{5}{11} [/tex]. 🙂 Reply

Step-by-step explanation:p(B) =favourable outcome/total outcome

=5/11

Answer:Given:–Abagcontains6redball’sand5blueball’soneballisdrawnofrandomfromthebag,whatistheprobabilityofgettingablueball.ToFind:–Probabilityofgettingablueball.Note:–●》Probability=●》Here,Numberoffavourableoutcomesisthebagcontainballsforwhichballwearefinding,Totalnumberofoutcomesistotalnumberofballs.Solution:–[tex] \huge\red{First, calculating \ \ missing \ \ values} [/tex]

## • Here, Number of favourable outcomes = 5 balls; Total number of outcomes = ?

☆Accordingtonotesecondpoint~▪︎[tex] Total \ \ number \ \ of \ \ outcomes = Total \ \ number \ \ of \ \ balls ( red + blue \ \ balls ) [/tex]

▪︎[tex] Total \ \ number \ \ of \ \ outcomes = 5 + 6 \ \ balls [/tex]

▪︎[tex] Total \ \ number \ \ of \ \ outcomes = 11 \ \ balls [/tex]

[tex] \huge\green{Total \ \ number \ \ of \ \ outcomes = 11 \ \ balls} [/tex]

______________________________________________[tex] \huge\red{ Now, we \ \ will \ \ calculate \ \ Probability } [/tex]

## • Number of favourable outcomes = 5 balls, Total number of outcomes = 11 balls, Probability = ?

☆Accordingtonotefirstpoint~▪︎[tex] Probability = \frac{Number \ \ of \ \ favourable \ \ outcomes}{Total \ \ number \ \ of \ \ outcomes} [/tex]

▪︎[tex] Probability = \frac{5 \ \ balls}{11 \ \ balls} [/tex]

☆Here,calculationscan’tbedonesosimplyleaveitandballs-ballswillbecanceled~▪︎[tex] Probability = \frac{5}{11} [/tex]

[tex] \huge\green{Probability = \frac{5}{11}} [/tex]

Answer:–Hence,theProbabilityofgettingblueballis🙂