A bag contains 4 red balls, 3 yellow balls and 5 green balls. A ball is drawn from the bag without looking into it. What is the probability of getting a green ball? About the author Skylar
Answer: Probability of getting a green ball is 5/12 Step-by-step explanation: S={R1, R2, R3, R4, Y1, Y2, Y3, G1, G2, G3, G4, G5} n(S)= 12 Let Event A = Getting a green ball A={G1, G2, G3, G4, G5} n(A)= 5 P(A)= n(A)/n(S) = 5/12 Reply
Answer:
Probability of getting a green ball is 5/12
Step-by-step explanation:
S={R1, R2, R3, R4, Y1, Y2, Y3, G1, G2, G3, G4, G5}
n(S)= 12
Let Event A = Getting a green ball
A={G1, G2, G3, G4, G5}
n(A)= 5
P(A)= n(A)/n(S)
= 5/12
Answer:
5/12
the number of green balls dived by the total number of balls.