A bag contains 4 red balls, 3 yellow balls and 5 green balls. A ball is drawn from the bag without looking into it. What is the probability of getting a green ball? About the author Skylar

Answer: Probability of getting a green ball is 5/12 Step-by-step explanation: S={R1, R2, R3, R4, Y1, Y2, Y3, G1, G2, G3, G4, G5} n(S)= 12 Let Event A = Getting a green ball A={G1, G2, G3, G4, G5} n(A)= 5 P(A)= n(A)/n(S) = 5/12 Reply

Answer:Probability of getting a green ball is 5/12

Step-by-step explanation:S={R1, R2, R3, R4, Y1, Y2, Y3, G1, G2, G3, G4, G5}

n(S)= 12

Let Event A = Getting a green ball

A={G1, G2, G3, G4, G5}

n(A)= 5

P(A)= n(A)/n(S)

= 5/12

Answer:5/12the number of green balls dived by the total number of balls.