A bag contains 4 red balls, 3 yellow balls and 5 green balls. A ball is drawn from the bag
without looking into it. What is

A bag contains 4 red balls, 3 yellow balls and 5 green balls. A ball is drawn from the bag
without looking into it. What is the probability of getting a green ball?

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2 thoughts on “A bag contains 4 red balls, 3 yellow balls and 5 green balls. A ball is drawn from the bag<br /> without looking into it. What is”

  1. Answer:

    Probability of getting a green ball is 5/12

    Step-by-step explanation:

    S={R1, R2, R3, R4, Y1, Y2, Y3, G1, G2, G3, G4, G5}

    n(S)= 12

    Let Event A = Getting a green ball

    A={G1, G2, G3, G4, G5}

    n(A)= 5

    P(A)= n(A)/n(S)

         = 5/12

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