A bag contains 3 red balls and 4 black balls. A balls is selected at random from the bag, what is the probability that the ball se

2 thoughts on “A bag contains 3 red balls and 4 black balls. A balls is selected at random from the bag, what is the probability that the ball se”

1. Answer:

   1)Black – 4/7

   2)Red – 3/7

   Step-by-step explanation:

   Probability = Number of observations

   —————————————-

   Total number of outcomes

   Data ,

   Red balls – 3

   Black balls – 4

   Total balls – 7

   1) P(getting a red ball) = 3/7

   2) P(getting a black ball) = 4/7

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2. Answer:

   1) 3/7

   2) 4/7

   Step-by-step explanation:

   let black balls be b1, b2, b3 and red balls be r1, r2, r3, r4

   Let ‘s’ be the sample space

   S={b1, b2, b3, r1,r2,r3,r4}

   n(S) =7

   Let ‘A’ be the event 1) black

   A={b1, b2, b3}

   n(A) =3

   p(A) =n(A) /n(S)

   =3/7

   Let ‘B’ be the event 2) red

   B={r1, r2, r3, r4}

   n(B) =4

   p(B) =n(B) /n(S)

   =4/7

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