A B C and D are four points on level ground. The bearing of C from Dis 118° and
the beaning of A from C is 254°
118°
D
N
3.4 km
N
126°
254°
B
2.6 km
Given that AB = 2.6 km, CD = 3.4 km, LABD = 126° and ABC is a straight line, find
(i) the bearing of B from D,
(ii) the distance between B and D,
(iii) the distance between A and D,
(iv) the shortest distance from B to AD.
lacb=1100 yaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
Answer:
The diagram shows points A, B, C and D on level ground. AD = 50 m … The distance AC = 20 km, BC = 15 km and LACB = 1100. Calculate.