A and B can do a piece of work in 15 days. B and C can do the same work in 10 days and A and C can do the same work in 12 days. Time taken by A, B and C together to do the job is? About the author Josephine
Step-by-step explanation: Here First we find efficiency of the work done by A, B and C :- A + B = 15 B + C = 10 C + A = 12 LCM of 15, 10, 12 will give it 60 ( Which is Total Work Done ) So efficiency of A + B is = 60 / 15 = 4 —–( 1 ) B + C is = 60 / 10 = 6 —–( 2 ) C + A is = 60 / 12 = 5 —–( 3 ) So Adding (1) (2) and (3) eq-n. We get :- 2 ( A + B + C ) = 15 A + B + C = 15/2 Ans. So time taken by A B and C to do this job in a day is 7. 5. PLEASE MARK MY ANSWER AS BRAIN LIST. Reply
Answer: LET ‘A’ IS CAPABLE OF DOING THE ENTIRE WORK INDIVIDUALLY IN X DAYS. SIMILARLY LET ‘B’ AND ‘C’ COMPLETE INDIVIDUALLY IN ‘Y’ AND ‘Z’ DAYS. THEN ( 10/X) + (10/Y) = 1; i.e 10{(X+Y)/XY = 1 ———————- (1) SIMILARLY 12(Y+Z)/YZ = 1 ———————————————— (2) AND 15(Z+X)/XZ = 1 ———————————————————-(3) REWRITING (1/X)+(1/Y) = (1/10) ————————(4) (1/Y) + (1/Z) = (1/12) ——————————————-(5) (1/X ) + (1/Z) = 1/15 ——————————————(6) SOLVING THE SIMULTANEOUS EQUATIONS ‘X’ = 24, ‘Y’ = 120/7, ‘Z’ = 40 IF A,B AND C ARE WORKING TOGETHER THE WORK THAT COULD BE COMPLETED IN A SINGLE DAY = (1/X) + (1/Y) + (1/Z) = (1/24) + (7/120) + (1/40) = (5+7+3)/120 = 15/120 = 1/8 THE NUMBER OF DAYS REQUIRED TO COMPLETE THE WORK = 1/*1/8) = 8 Reply
Step-by-step explanation:
Here First we find efficiency of the work done by A, B and C :-
A + B = 15
B + C = 10
C + A = 12
LCM of 15, 10, 12 will give it 60 ( Which is Total Work Done )
So efficiency of A + B is = 60 / 15 = 4 —–( 1 )
B + C is = 60 / 10 = 6 —–( 2 )
C + A is = 60 / 12 = 5 —–( 3 )
So Adding (1) (2) and (3) eq-n. We get :-
2 ( A + B + C ) = 15
A + B + C = 15/2 Ans.
So time taken by A B and C to do this job in a day is 7. 5.
PLEASE MARK MY ANSWER AS BRAIN LIST.
Answer:
LET ‘A’ IS CAPABLE OF DOING THE ENTIRE WORK INDIVIDUALLY IN X DAYS.
SIMILARLY LET ‘B’ AND ‘C’ COMPLETE INDIVIDUALLY IN ‘Y’ AND ‘Z’ DAYS.
THEN ( 10/X) + (10/Y) = 1; i.e 10{(X+Y)/XY = 1 ———————- (1)
SIMILARLY 12(Y+Z)/YZ = 1 ———————————————— (2)
AND 15(Z+X)/XZ = 1 ———————————————————-(3)
REWRITING (1/X)+(1/Y) = (1/10) ————————(4)
(1/Y) + (1/Z) = (1/12) ——————————————-(5)
(1/X ) + (1/Z) = 1/15 ——————————————(6)
SOLVING THE SIMULTANEOUS EQUATIONS
‘X’ = 24, ‘Y’ = 120/7, ‘Z’ = 40
IF A,B AND C ARE WORKING TOGETHER THE WORK THAT COULD BE COMPLETED IN A SINGLE DAY
= (1/X) + (1/Y) + (1/Z) = (1/24) + (7/120) + (1/40) = (5+7+3)/120 = 15/120 = 1/8
THE NUMBER OF DAYS REQUIRED TO COMPLETE THE WORK = 1/*1/8) = 8