A 5 gm bullet is fired at a fixed target with a speed of 500 m/s , During penetration the target offered a resistance of 1000 N to

1 thought on “A 5 gm bullet is fired at a fixed target with a speed of 500 m/s , During penetration the target offered a resistance of 1000 N to”

1. Given,

   mass=5g

   speed=500m/s

   force=1000N

   (a) kinetic energy=

   2

   1

   ×m×v×v

   m=5g=

   1000

   5

   kg

   v=500

   ⇒

   2

   1

   ×

   1000

   5

   ×500×500

   =625J

   (b) force=mass×acceleration

   1000=

   1000

   5

   ×acceleration

   Acceleration=1000×

   5

   1000

   =200000m/s

   2

   using the third equation of motion

   v

   2

   =u

   2

   +2as

   (500)

   2

   =0+2×200000×s

   250000=400000×s

   s=0.625m

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