[tex] \large \{ \overbrace {\underbrace{ \bold {\pmb { \: \: \blue{ QU ESTION } \: \: }}}} \}[/tex] Time Period of a Simple Pendulum in a Freely Falling Lift will be About the author Sophia
EXPLAINATION Formula for Time Period Time period, t = 2π √(t/g) Where t → time period g → acceleration due to gravity During free fall the body feels weightless inside the lift or no Acceleration will be acting on the body So, g = 0 NOW ∴ Time period, t = 2π √(t/0) = 2π √∞ = ∞ Thus, the time period of a simple pendulum in a freely falling lift will be infinity (∞). [tex]\\[/tex] ▬▭▬▭▬▭▬▭▬▭▬▭▬▭▬▭▬▭▬▭▬ Reply
[tex]{\huge{\boxed{\tt{\color {red}{Answer❀✿°᭄}}}}}[/tex] During free fall the body feels weightless inside the lift. Hence, the time period of a simple pendulum in a freely falling lift will be infite(∞). [tex]\huge\mathfrak\pink{itz \: Sujitha}[/tex] Reply
EXPLAINATION
Formula for Time Period
Time period, t = 2π √(t/g)
Where
During free fall the body feels weightless inside the lift or no Acceleration will be acting on the body So, g = 0
NOW
∴ Time period, t
Thus, the time period of a simple pendulum in a freely falling lift will be infinity (∞).
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[tex]{\huge{\boxed{\tt{\color {red}{Answer❀✿°᭄}}}}}[/tex]
During free fall the body feels weightless inside the lift. Hence, the time period of a simple pendulum in a freely falling lift will be infite(∞).
[tex]\huge\mathfrak\pink{itz \: Sujitha}[/tex]