what number must be subtracted from each term of the ratio 17:33 so that the ratio become 7:15

Question

what number must be subtracted from each term of the ratio 17:33 so that the ratio become 7:15​

Autumn · Answer

Answer:   3   Step-by-step explanation:   Suppose that x is the number that must be subtracted.  Then, (17 − x) : (33 − x) = 7 : 15    ⇒17 − x33 − x=715⇒255 − 15x = 231 − 7x ⇒8x = 255 − 231 = 24⇒x = 3    Hence, 3 must be subtracted from each term of ratio 17 : 33 so that it becomes 7 : 15.

Everleigh · Answer

Answer:   3     Step-by-step explanation:   Suppose that x is the number that must be subtracted. Hence, 3 must be subtracted from each term of ratio 17 : 33 so that it becomes 7 : 15.

Margaret

3x-7/2 – 2y-8/3=-1;5-x/3 – 3-2y/7 by equating cofficient.i think you are all donkeys. you can’t say a small question answer

if three numbers are in the ratio of 2:3:5 and half of their sum is 20 then what is the ratio of squares of the numbers

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