if the peremeter of a square is 120cm find its area and length of diagonal​

2 thoughts on “if the peremeter of a square is 120cm find its area and length of diagonal​”

1. Step-by-step explanation:

   Area of rhombus =1/2 D1*D2 =1/2 *10 *d2 =120

   D2 =120/4 =24

   Half of D1=10/2 =5

   Half of D2=24/2 =12

   Side = sq root of [5^2+12^2]= sq root of[25+144]

   sq root of[169] =13

   perimeter =13*4 =52cms

   Answer : perimeter is =52cms

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2. [tex]\bold{\tt{\red{\bigstar \: Solution : }}}\\[/tex]

   [tex]\:[/tex]

   [tex]\tt{\green{perimeter \: of \: square = 120cm}}\\[/tex]

   [tex]\tt{\green{\implies 4 \times side = 120cm}}\\[/tex]

   [tex]\tt{\green{\implies side = \frac{120cm}{4}}}\\[/tex]

   [tex]\tt{\green{\implies side = 30cm}}\\[/tex]

   [tex]\:[/tex]

   [tex]\tt{\orange{area \: of \: square = {(side)}^2}}\\[/tex]

   [tex]\tt{\orange{\implies area \: of \: square = {(30cm)}^2}}\\[/tex]

   [tex]\tt{\orange{\implies area \: of \: square = {900cm}^2}}\\[/tex]

   [tex]\:[/tex]

   [tex]\tt{diagonal \: of \: square = \sqrt{2 \times {(side)}^2}}\\[/tex]

   [tex]\tt{\implies diagonal \: of \: square = \sqrt{2 \times {(30cm)}^2}}\\[/tex]

   [tex]\tt{\implies diagonal \: of \: square = \sqrt{{900cm}^2}}\\[/tex]

   [tex]\tt{\implies diagonal \: of \: square = \sqrt{ {1800cm}^2}}\\[/tex]

   [tex]\tt{\implies diagonal \: of \: square = 42.42cm}\\[/tex]

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