In the given figure ,
O is the centre of the circle and
ACB is inscribed in arc ACB.
If ACB = 650

In the given figure ,
O is the centre of the circle and
ACB is inscribed in arc ACB.
If ACB = 650

, then find m(arcAPB).

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1 thought on “In the given figure ,<br /> O is the centre of the circle and<br /> ACB is inscribed in arc ACB.<br /> If ACB = 650<br /><br />”

  1. 一═デ︻ αηѕωєя ︻デ═一

    m(arc ACB)=230°

    Explanation:

    Given : ∠ACB is inscribed in a arc ACB of a circle with centre O.

    ∠ACB =65°

    The Inscribed Angle Theorem : The measure of an inscribed angle is half the measure the arc intercepted by it.

    Therefore , ∠ACB= half of Measure of arc AB

    ⇒Measure of arc AB = 2 x ∠ACB = 2 x 65° =130°

    Since arcAB is minor arc and arc ACb is major arc and tyhe sum of minor and major arc is 360°.

    ⇒ Measure of Major arc = 360°- Minor arc

    ⇒ Measure of arc ACB = 360° -130°

    =230°

    Hence, m(arc ACB) =230°

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