Given :- Diagonals are 16 cm and 7 cm. To find :- Area of the Rhombus Solution :- [tex]\boxed{ \pmb{\tt Area \: of \: rhombus = \dfrac{1}{2}\times diagonal_1 \times diagonal_2}}[/tex] [tex] \sf{= \dfrac{1}{2} \times 16 \times 7}[/tex] [tex]\sf{ = \frac{112}{2}}[/tex] [tex]\sf{ = \blue{ 56}}[/tex] Area is 56 cm². _____♡Ilina♡______ Reply
Given : Diagonals are 16 cm and 7 cm. To find : Area Solution : [tex] \boxed{ \pmb{\tt Area \: of \: rhombus = \dfrac{1}{2}\times diagonal_1 \times diagonal_2}} [/tex] [tex] \tt \leadsto \dfrac{1}{2} \times 16 \times 7[/tex] [tex] \tt \leadsto \dfrac{112}{2} [/tex] [tex] \tt \leadsto 56 [/tex] Area is 56 cm². Reply
Given :-
Diagonals are 16 cm and 7 cm.
To find :-
Area of the Rhombus
Solution :-
[tex]\boxed{ \pmb{\tt Area \: of \: rhombus = \dfrac{1}{2}\times diagonal_1 \times diagonal_2}}[/tex]
[tex] \sf{= \dfrac{1}{2} \times 16 \times 7}[/tex]
[tex]\sf{ = \frac{112}{2}}[/tex]
[tex]\sf{ = \blue{ 56}}[/tex]
Area is 56 cm².
_____♡Ilina♡______
Given :
Diagonals are 16 cm and 7 cm.
To find :
Solution :
[tex] \boxed{ \pmb{\tt Area \: of \: rhombus = \dfrac{1}{2}\times diagonal_1 \times diagonal_2}} [/tex]
[tex] \tt \leadsto \dfrac{1}{2} \times 16 \times 7[/tex]
[tex] \tt \leadsto \dfrac{112}{2} [/tex]
[tex] \tt \leadsto 56 [/tex]
Area is 56 cm².