[tex]fill \: the \: box \: \frac{3}{5} | \: \: \: \: | \frac{12}{91} [/tex] fill the box 3/5__12/91 About the author Natalia
Answer: The LCM of 5 and 91 is 455. [tex] \frac{3}{5} = \frac{3 \times 91}{5 \times 91} = \frac{273}{455} [/tex] [tex] \frac{12}{91} = \frac{12 \times 5}{91 \times 5} = \frac{60}{455} [/tex] since, [tex]273 > 60[/tex] therefore, [tex] \frac{273}{455} > \frac{60}{455} [/tex] [tex] = > \: \frac{3}{5} > \frac{12}{91} [/tex] HOPE IT WORKS OUT FOR YOU AND PLEASE F-O-L-L-O-W ME AND MARK ME BRAINLIEST. Reply
Answer: L.C.M. of 5 and 91 = 5 × 91 = 455 [tex] \frac{3}{5} = \frac{3 \times 91}{5 \times 91} = \frac{273}{455} [/tex] [tex] \frac{12}{91} = \frac{12 \times 5}{91 \times 5} = \frac{60}{455} [/tex] Clearly, [tex]273 > 60 \\ = > \frac{273}{455} > \frac{60}{455} [/tex] Hence, [tex] \frac{3}{5} > \frac{12}{91} [/tex] Hope it helps you. Please mark my answer brainliest. Reply
Answer:
The LCM of 5 and 91 is 455.
[tex] \frac{3}{5} = \frac{3 \times 91}{5 \times 91} = \frac{273}{455} [/tex]
[tex] \frac{12}{91} = \frac{12 \times 5}{91 \times 5} = \frac{60}{455} [/tex]
since,
[tex]273 > 60[/tex]
therefore,
[tex] \frac{273}{455} > \frac{60}{455} [/tex]
[tex] = > \: \frac{3}{5} > \frac{12}{91} [/tex]
HOPE IT WORKS OUT FOR YOU AND PLEASE F-O-L-L-O-W ME AND MARK ME BRAINLIEST.
Answer:
L.C.M. of 5 and 91 = 5 × 91 = 455
[tex] \frac{3}{5} = \frac{3 \times 91}{5 \times 91} = \frac{273}{455} [/tex]
[tex] \frac{12}{91} = \frac{12 \times 5}{91 \times 5} = \frac{60}{455} [/tex]
Clearly,
[tex]273 > 60 \\ = > \frac{273}{455} > \frac{60}{455} [/tex]
Hence,
[tex] \frac{3}{5} > \frac{12}{91} [/tex]
Hope it helps you.
Please mark my answer brainliest.