In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B is : A) 19 B) 29 C) 39 D) 49 About the author Vivian
Given In 10 years, A will be twice as old as B was 10 years ago. A is now 9 years older than B. Explanation Let the present age of B be x years and present age of A be (x+9) years. ✮After 10 years, Age of A = (x + 9 + 10) years ✮Before 10 years, Age of B be = (x − 10) years ✮Now, We’ve to compare the both equations to find the desired results as:- [tex] \\ \colon\implies{\sf{ (x+9+10)=2(x−10)}} \\ \\ \\ \colon\implies{\sf{ x + 19 = 2x – 20 }} \\ \\ \\ \colon\implies{\sf{ 19 + 20 = 2x – x }} \\ \\ \\ \colon\implies{\sf{ x = 39 \ years}} \\ [/tex] Hence, [tex] \\ {\underline{\sf{ The \ present \ age \ of \ B \ is \ 39 \ years. }}} \bigstar \\ [/tex] Reply
Answer:
B) 29
Step-by-step explanation:
please mark me branliest
Given
Explanation
Let the present age of B be x years and present age of A be (x+9) years.
✮After 10 years,
✮Before 10 years,
✮Now, We’ve to compare the both equations to find the desired results as:-
[tex] \\ \colon\implies{\sf{ (x+9+10)=2(x−10)}} \\ \\ \\ \colon\implies{\sf{ x + 19 = 2x – 20 }} \\ \\ \\ \colon\implies{\sf{ 19 + 20 = 2x – x }} \\ \\ \\ \colon\implies{\sf{ x = 39 \ years}} \\ [/tex]
Hence,
[tex] \\ {\underline{\sf{ The \ present \ age \ of \ B \ is \ 39 \ years. }}} \bigstar \\ [/tex]