Find the value of k, if the roots of the quadratic equation 2×2-6×+k=0 are real and equal About the author Autumn
Answer: 9 Step-by-step explanation: Comparing the question with ax²+by+c=0, we get, a=1; b=-6; c=k b2-4ac=0 (-6)²-4×1×k=0 36-4k=0 36=4k k=9 (4×9=36) Reply
Answer:
9
Step-by-step explanation:
Comparing the question with ax²+by+c=0, we get,
a=1; b=-6; c=k
b2-4ac=0
(-6)²-4×1×k=0
36-4k=0
36=4k
k=9 (4×9=36)
Answer:
2
Step-by-step explanation:
2×2-6×+k=0
4-6×+k=0
-2×+k=0
+k=0+2
k=2