[tex]\Huge{\textbf{\textsf{{\color{navy}{Quê}}{\purple{sTi}}{\pink{øN}}{\color{pink}{:}}}}}[/tex]→ Given that (k-7) is the H.C.F. of 56 and 104, find the value of k. ← ~Only for ItzNawaabzadi12* About the author Everleigh
[tex]\huge{\underline{\underline{\bf{\purple{Answer}}}}}[/tex] HCF ( 56 , 104 ) = 0 K – 7 = 0 K = 7 Hence , value of k = 7 . Reply
Answer: [tex]\huge\mathfrak\pink{Answer!}[/tex] The Highest Common factor of 56 and 104 is 8 It is given that (k-7) is the HCF of 56 and 104 so, k-7 = 8 k = 8 + 7 k = 15 Therefore the value of k is 15 HOPE IT HELPS #NAWABZAADI Reply
[tex]\huge{\underline{\underline{\bf{\purple{Answer}}}}}[/tex]
HCF ( 56 , 104 ) = 0
K – 7 = 0
K = 7
Hence , value of k = 7 .
Answer:
[tex]\huge\mathfrak\pink{Answer!}[/tex]
The Highest Common factor of 56 and 104 is 8
It is given that (k-7) is the HCF of 56 and 104
so, k-7 = 8
k = 8 + 7
k = 15
Therefore the value of k is 15
HOPE IT HELPS
#NAWABZAADI