In a parallelogram ABCD, if A = (3x – 8)° and
∆D = (2x + 13)°, find the value of x and the measure
of each angle of the

In a parallelogram ABCD, if A = (3x – 8)° and
∆D = (2x + 13)°, find the value of x and the measure
of each angle of the parallelogram.

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2 thoughts on “In a parallelogram ABCD, if A = (3x – 8)° and<br />∆D = (2x + 13)°, find the value of x and the measure<br />of each angle of the”

  1. Answer:

    3x-8+2x+13 = 180

    3x+2x-8+13 = 180

    5x+5 = 130

    5x = 125

    x = 25

    A = 3x-8

    = 3 x 25 – 8

    = 75-8

    therefore A = 67°

    D = 2x + 13

    = 2 x 25 + 13

    = 50 + 13

    = 63

    therefore D = 63°

    therefore the angles are 67°,63°,67°,63°.

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