The area of a rectangular plot is increased by
30% and its width remain as it was before. What
will be the ratio between

The area of a rectangular plot is increased by
30% and its width remain as it was before. What
will be the ratio between the area of new
rectangle and the original rectangle?
1. 13:10
2: 10:13
3. 7:3
4. 3:7​

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Madelyn

2 thoughts on “The area of a rectangular plot is increased by<br />30% and its width remain as it was before. What<br />will be the ratio between”

  1. Given :-

    Area of rectangular plot increased by 30%

    To find :-

    Ratio between new and original rectangle

    Solution :-

    Let the

    Original rectangle’s area = y

    New rectangle area

    (100 + increased percentage) of original rectangle

    [tex]\sf \bigg(100 + 30\bigg) \times y[/tex]

    [tex]\sf \dfrac{100 + 30}{100} \times y[/tex]

    [tex]\sf \dfrac{130}{100}\times y[/tex]

    [tex]\sf \dfrac{13}{10}y[/tex]

    Finding ratio

    [tex]\sf \dfrac{13}{10}y = y[/tex]

    [tex]\sf 13y = 10\times y[/tex]

    [tex]\sf 13y = 10y[/tex]

    [tex]\sf 13 =10[/tex]

    Ratio = 13:10 [Option A]

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  2. Answer:

    1. 13 : 10 is the required answer.

    Step-by-step explanation:

    Given that:

    • The area of a rectangular plot is increased by 30% and its width remain as it was before.

    To Find:

    • What will be the ratio between the area of new rectangle and the original rectangle?

    Let us assume:

    • Area of original rectangle be x cm².

    Finding the ratio between the area of new rectangle and the original rectangle:

    Area of new rectangle : Area of original rectangle

    ⟶ (100 + 30)% of x : x

    ⟶ 130% of x : x

    ⟶ 1.3 of x : x

    ⟶ 1.3x : x

    Cancelling x.

    ⟶ 1.3 : 1

    Multiplying by 10.

    ⟶ (1.3 × 10) : (1 × 10)

    ⟶ 13 : 10

    ∴ The ratio between the area of new rectangle and the original rectangle = 13 : 10

    Reply

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