The area of a rectangular plot is increased by
30% and its width remain as it was before. What
will be the ratio between

2 thoughts on “The area of a rectangular plot is increased by<br />30% and its width remain as it was before. What<br />will be the ratio between”

1. Given :-

   Area of rectangular plot increased by 30%

   To find :-

   Ratio between new and original rectangle

   Solution :-

   Let the

   Original rectangle’s area = y

   New rectangle area

   (100 + increased percentage) of original rectangle

   [tex]\sf \bigg(100 + 30\bigg) \times y[/tex]

   [tex]\sf \dfrac{100 + 30}{100} \times y[/tex]

   [tex]\sf \dfrac{130}{100}\times y[/tex]

   [tex]\sf \dfrac{13}{10}y[/tex]

   Finding ratio

   [tex]\sf \dfrac{13}{10}y = y[/tex]

   [tex]\sf 13y = 10\times y[/tex]

   [tex]\sf 13y = 10y[/tex]

   [tex]\sf 13 =10[/tex]

   Ratio = 13:10 [Option A]

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2. Answer:

   1. 13 : 10 is the required answer.

   Step-by-step explanation:

   Given that:

   • The area of a rectangular plot is increased by 30% and its width remain as it was before.

   To Find:

   • What will be the ratio between the area of new rectangle and the original rectangle?

   Let us assume:

   • Area of original rectangle be x cm².

   Finding the ratio between the area of new rectangle and the original rectangle:

   Area of new rectangle : Area of original rectangle

   ⟶ (100 + 30)% of x : x

   ⟶ 130% of x : x

   ⟶ 1.3 of x : x

   ⟶ 1.3x : x

   Cancelling x.

   ⟶ 1.3 : 1

   Multiplying by 10.

   ⟶ (1.3 × 10) : (1 × 10)

   ⟶ 13 : 10

   ∴ The ratio between the area of new rectangle and the original rectangle = 13 : 10

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