✍️A᭄NSWER✍️ ʟᴇᴛ ᴛʜᴇ ᴛᴡᴏ ᴘᴀʀᴛs ʙᴇ x ᴀɴᴅ x − 15. [tex] \frac{1}{x} + \frac{1}{15 – x} = \frac{3}{10} [/tex] [tex] \frac{15 – x + x}{x(15 – x} = \frac{3}{10} [/tex] [tex] \frac{15}{15x – {x}^{2} } \ = \frac{3}{10} [/tex] ➪ 150 = 145 – 3x^2 ➪ 3x^2 – 45x + 150 = 0 ➪ x^2 – 15x + 150 = 0 ➪ (x-5) (x-10) ➪ x = 5 , 10 x = 5 ⟹ ᴏɴᴇ ᴘᴀʀᴛ = 5 ᴀɴᴅ ᴏᴛʜᴇʀ ᴘᴀʀᴛ = 10 x = 10 ⟹ ᴏɴᴇ ᴘᴀʀᴛ = 10 ᴀɴᴅ ᴏᴛʜᴇʀ ᴘᴀʀᴛ = 5 ᴛʜᴜs, ᴛʜᴇ ʀᴇǫᴜɪʀᴇᴅ ᴛᴡᴏ ᴘᴀʀᴛs ᴀʀᴇ 5 ᴀɴᴅ 10. ╚─━━━━━░★░━━━━━─╝ Reply
Step-by-step explanation: first condition x+y=15____(1) by second condition 1/x + 1/y = 3/10 3x + 3y =10____(2) multiply equation (1) by 3 3x+3y = 45____(3) add and subtract equation (2) & (3) addition: 6x+6y = 55___(4) subtraction :o=35_____(5) add (4)&(5) 6x+6y = 90 Reply
✍️A᭄NSWER✍️
ʟᴇᴛ ᴛʜᴇ ᴛᴡᴏ ᴘᴀʀᴛs ʙᴇ x ᴀɴᴅ x − 15.
[tex] \frac{1}{x} + \frac{1}{15 – x} = \frac{3}{10} [/tex]
[tex] \frac{15 – x + x}{x(15 – x} = \frac{3}{10} [/tex]
[tex] \frac{15}{15x – {x}^{2} } \ = \frac{3}{10} [/tex]
➪ 150 = 145 – 3x^2
➪ 3x^2 – 45x + 150 = 0
➪ x^2 – 15x + 150 = 0
➪ (x-5) (x-10)
➪ x = 5 , 10
x = 5
⟹ ᴏɴᴇ ᴘᴀʀᴛ = 5 ᴀɴᴅ ᴏᴛʜᴇʀ ᴘᴀʀᴛ = 10 x = 10
⟹ ᴏɴᴇ ᴘᴀʀᴛ = 10 ᴀɴᴅ ᴏᴛʜᴇʀ ᴘᴀʀᴛ = 5 ᴛʜᴜs,
ᴛʜᴇ ʀᴇǫᴜɪʀᴇᴅ ᴛᴡᴏ ᴘᴀʀᴛs ᴀʀᴇ 5 ᴀɴᴅ 10.
╚─━━━━━░★░━━━━━─╝
Step-by-step explanation:
first condition
x+y=15____(1)
by second condition
1/x + 1/y = 3/10
3x + 3y =10____(2)
multiply equation (1) by 3
3x+3y = 45____(3)
add and subtract equation (2) & (3)
addition: 6x+6y = 55___(4)
subtraction :o=35_____(5)
add (4)&(5)
6x+6y = 90