If tan 0 = 1, then the value of
8 sin A+5 cose
sin – 2 cos + 7 cos e
is​

1 thought on “If tan 0 = 1, then the value of<br />8 sin A+5 cose<br />sin – 2 cos + 7 cos e<br />is​”

1. Answer:

   tanθ=2

   Now, sin2θ+2cos2θ+3cosθ8sinθ+5cosθ

   = cos3θ×(tan3θ+2+cos2θ3)cosθ(8tanθ+5)

   = tan3θ+2+3sec2θsec2θ(8tanθ+5)=tan3θ+2+3(1+tan2θ)(1+tan2θ)(8tanθ+5)

   = 23+2+3(1+22)(1+22)(8×2+5)=10+155×21=25

   Reply