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Prove that ∆RSV ≅ ∆RKV, if RS = RK = 7 cm and RV = 5 cm and RV is perpendicular to SK.​

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Prove that ∆RSV ≅ ∆RKV, if RS = RK = 7 cm and RV = 5 cm and RV is perpendicular to SK.​

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Genesis

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2 thoughts on “Prove that ∆RSV ≅ ∆RKV, if RS = RK = 7 cm and RV = 5 cm and RV is perpendicular to SK.​”

  2. Step-by-step explanation:

    LengthofDE=3.5cm

    Step-by-step explanation:

    Midpoint Theorem:

    The line segment joining the midpoints of two sides of a triangle is parallel to the third side and also half of it .

    Given :

    In ∆ABC , AB = 5 cm ,

    BC = 8 cm,

    and CA = 7 cm ,

    D and E are respectively the midpoints of AB and BC .

    DE = \frac{1}{2} \times ACDE=21×AC

    = \frac{1}{2} \times 7=21×7

    = 3.5 \:cm=3.5cm

    Therefore.,

    \red { Length \: of \: DE } \green {= 3.5 \:cm }LengthofDE=3.5cm

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