Solve :
[tex] \frac{2x}{x – 4 } + \frac{1}{x – 2} + \frac{2}{x {}^{2} – 6x + 8 } = 0[/tex]
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1 thought on “Solve : <br />[tex] \frac{2x}{x – 4 } + \frac{1}{x – 2} + \frac{2}{x {}^{2} – 6x + 8 } = 0[/tex]<br />​”

1. Step-by-step explanation:

   =x−4

   2x

   +

   x−2

   1

   +

   (x−4)(x−2)

   2

   =0

   =2x(x−2)+x−4+2=0

   =2x²−3x−2=0

   =2x²+x−4x−2=0

   =x(2x+1)−2(2x+1)=0

   =(2x+1)(x−2)=0

   =x=− 1/2;2

   this is a answer for this question ⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️⁉️❓❓❓

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