46. 10 year ago the ages of A and B were in theratio 13:17, respectively. 17 year from now therespective ratioof their ages will be 10: 11. Whatis the age of B at present? About the author Liliana
C) 27 yr Description for Correct answer: Let the ages of A and B 10 yr before were 13x yr and 17x yr, respectively. Then, present age of A = 13x + 10 and present age of B = 17x + 10 According to the question, 13x+10+1717x+10+17=1011 13x+2717x+27=1011 Hence, present age of B = 17 x 1 + 10 = 27yr hope this helps you mark me as brainliest please Reply
Answer: Step-by-step explanation: Given, Ratio of ages of A and B , 10years ago = 13 : 17 Ratio of ages of A and B, after 17 years = 10 : 11 To Find:- Present age of B. Solution:- Let, the present age of :- A be ‘x’ B be ‘y’ Given, Ratio of ages of A and B , 10years ago = 13 : 17 Age of A ten years ago = x – 10 Age of B ten years ago = y – 10 [tex]\implies \frac{x – 10}{y-10} = \frac{13}{17}[/tex] let the constant be ‘z’ x – 10 = 13z x = 13x + 10 y – 10 = 17z y = 17z + 10 Given, Ratio of ages of A and B, after 17 years = 10 : 11 Age of A after 17 years = x + 17 Age of B after 17 years = y + 17 [tex]\implies\frac{x + 17}{y+17} = \frac{10}{11}[/tex] From above vlaues :- [tex]\implies \frac{13z + 10 + 17}{17z + 10 + 17} = \frac{10}{11}[/tex] 13z + 27/17z + 27 = 10/11 (13z + 27)11 = 10(17z + 27) 143z + 297 = 170z + 270 297 – 270 = 170z – 143z 27 = 27z z = 27/27 z = 1 since, Present age of B = y = 17z + 10 = 17(1) + 10 = 17 + 10 = 27 [tex]\sf\therefore[/tex] Present age of B = 27 Reply
C) 27 yr
Description for Correct answer:
Let the ages of A and B 10 yr before were 13x yr and 17x yr, respectively.
Then, present age of A = 13x + 10 and present age of B = 17x + 10
According to the question,
13x+10+1717x+10+17=1011
13x+2717x+27=1011
Hence, present age of B = 17 x 1 + 10 = 27yr
hope this helps you mark me as brainliest please
Answer:
Step-by-step explanation:
Given,
Ratio of ages of A and B , 10years ago = 13 : 17
Ratio of ages of A and B, after 17 years = 10 : 11
To Find:-
Present age of B.
Solution:-
Let,
the present age of :-
A be ‘x’
B be ‘y’
Given,
Ratio of ages of A and B , 10years ago = 13 : 17
Age of A ten years ago = x – 10
Age of B ten years ago = y – 10
[tex]\implies \frac{x – 10}{y-10} = \frac{13}{17}[/tex]
let the constant be ‘z’
x – 10 = 13z
x = 13x + 10
y – 10 = 17z
y = 17z + 10
Given,
Ratio of ages of A and B, after 17 years = 10 : 11
Age of A after 17 years = x + 17
Age of B after 17 years = y + 17
[tex]\implies\frac{x + 17}{y+17} = \frac{10}{11}[/tex]
From above vlaues :-
[tex]\implies \frac{13z + 10 + 17}{17z + 10 + 17} = \frac{10}{11}[/tex]
13z + 27/17z + 27 = 10/11
(13z + 27)11 = 10(17z + 27)
143z + 297 = 170z + 270
297 – 270 = 170z – 143z
27 = 27z
z = 27/27
z = 1
since,
Present age of B = y = 17z + 10
= 17(1) + 10
= 17 + 10
= 27
[tex]\sf\therefore[/tex] Present age of B = 27