46. 10 year ago the ages of A and B were in the
ratio 13:17, respectively. 17 year from now the
respective ratioof their

46. 10 year ago the ages of A and B were in the
ratio 13:17, respectively. 17 year from now the
respective ratioof their ages will be 10: 11. What
is the age of B at present?​

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2 thoughts on “46. 10 year ago the ages of A and B were in the<br />ratio 13:17, respectively. 17 year from now the<br />respective ratioof their”

  1. C) 27 yr

    Description for Correct answer:

    Let the ages of A and B 10 yr before were 13x yr and 17x yr, respectively.

    Then, present age of A = 13x + 10 and present age of B = 17x + 10

    According to the question,

    13x+10+1717x+10+17=1011

    13x+2717x+27=1011

    Hence, present age of B = 17 x 1 + 10 = 27yr

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  2. Answer:

    Step-by-step explanation:

    Given,

    Ratio of ages of A and B , 10years ago = 13 : 17

    Ratio of ages of A and B, after 17 years = 10 : 11

    To Find:-

    Present age of B.

    Solution:-

    Let,

    the present age of :-

    A be ‘x’

    B be ‘y’

    Given,

    Ratio of ages of A and B , 10years ago = 13 : 17

    Age of A ten years ago = x – 10

    Age of B ten years ago = y – 10

    [tex]\implies \frac{x – 10}{y-10} = \frac{13}{17}[/tex]

    let the constant be ‘z’

    x – 10 = 13z

    x = 13x + 10

    y – 10 = 17z

    y = 17z + 10

    Given,

    Ratio of ages of A and B, after 17 years = 10 : 11

    Age of A after 17 years = x + 17

    Age of B after 17 years = y + 17

    [tex]\implies\frac{x + 17}{y+17} = \frac{10}{11}[/tex]

    From above vlaues :-

    [tex]\implies \frac{13z + 10 + 17}{17z + 10 + 17} = \frac{10}{11}[/tex]

    13z + 27/17z + 27 = 10/11

    (13z + 27)11 = 10(17z + 27)

    143z + 297 = 170z + 270

    297 – 270 = 170z – 143z

    27 = 27z

    z = 27/27

    z = 1

    since,

    Present age of B = y = 17z + 10

    = 17(1) + 10

    = 17 + 10

    = 27

    [tex]\sf\therefore[/tex] Present age of B = 27

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