In triangle OPQ, right angled at P, OP-7cm and OQ-PQ = lem determine the value of Sin 8 and Cos 0. About the author Josie
Step-by-step explanation: Answer In Δ OPQ, we have OQ 2 =OP 2 +PQ 2 ⇒(PQ+1) 2 =OP 2 +PQ 2 [∵OQ−PQ=1⇒OQ=1+PQ] ⇒PQ 2 +2PQ+1=OP 2 +PQ 2 ⇒2PQ+1=49 ⇒PQ=24cm ∴OQ−PQ=1cm ⇒OQ=(PQ+1)cm=25cm Now, sinQ= OQ OP = 25 7 and, cosQ= OQ PQ = 25 24 Reply
Step-by-step explanation:
Answer
In Δ OPQ, we have
OQ
2
=OP
2
+PQ
2
⇒(PQ+1)
2
=OP
2
+PQ
2
[∵OQ−PQ=1⇒OQ=1+PQ]
⇒PQ
2
+2PQ+1=OP
2
+PQ
2
⇒2PQ+1=49
⇒PQ=24cm
∴OQ−PQ=1cm
⇒OQ=(PQ+1)cm=25cm
Now, sinQ=
OQ
OP
=
25
7
and, cosQ=
OQ
PQ
=
25
24