in triangle ABC &D and E are points on the sides AB and AC respectively if is equal to AD=1.5 cm is DB= 3cm and EC=2cmfind AE About the author Lyla
Answer: DE∣∣BC ⟹∠ADE=∠ABC Corresponding angles ∠AED=∠ACB Corresponding angles ∠A is common to both the triangles. ∴ΔADE∼ΔABC by AAA similarity ⟹ AD AB = AE AC AD AB −1= AE AC −1 AD BD = AE CE EC=1× 1.5 3 =2 cm Step-by-step explanation: Mark me as brainlist Reply
Step-by-step explanation: The given information is shown in the attached diagram. DE∣∣BC ⟹∠ADE=∠ABC Corresponding angles ∠AED=∠ACB Corresponding angles ∠A is common to both the triangles. ∴ΔADE∼ΔABC by AAA similarity ⟹ AD AB = AE AC AD AB −1= AE AC −1 AD BD = AE CE EC=1× 1.5 3 =2 cm Reply
Answer:
DE∣∣BC
⟹∠ADE=∠ABC Corresponding angles
∠AED=∠ACB Corresponding angles
∠A is common to both the triangles.
∴ΔADE∼ΔABC by AAA similarity
⟹
AD
AB
=
AE
AC
AD
AB
−1=
AE
AC
−1
AD
BD
=
AE
CE
EC=1×
1.5
3
=2 cm
Step-by-step explanation:
Mark me as brainlist
Step-by-step explanation:
The given information is shown in the attached diagram.
DE∣∣BC
⟹∠ADE=∠ABC Corresponding angles
∠AED=∠ACB Corresponding angles
∠A is common to both the triangles.
∴ΔADE∼ΔABC by AAA similarity
⟹
AD
AB
=
AE
AC
AD
AB
−1=
AE
AC
−1
AD
BD
=
AE
CE
EC=1×
1.5
3
=2 cm