In an arithemetic sequence 5th term 10 and common difference 2 find 15th term,20th term, 50th term. About the author Isabella
Answer: Formula : Tn = a+(n-1)d / where d =2 T5 = 10 10 = a+(5-1)2 10 = a+8 a = 2 T15 = a+14d =2+14(2) = 2+28 =30 T20 = a+19d =2+(19)2 = 2+38 =40 T50 = a+49d = 2+(49)2 =2+98 = 100 Please like .. Reply
Answer:
Formula : Tn = a+(n-1)d / where d =2
T5 = 10
10 = a+(5-1)2
10 = a+8
a = 2
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