Answer: Step-by-step explanation: assume that 1/[tex]\sqrt{2\\}[/tex] is rational 1/[tex]\sqrt{2\\}[/tex]=a/b,where a and b are integers 1/[tex]\sqrt{2\\}[/tex]=a/b [tex]\sqrt{2\\}[/tex]/1=b/a [tex]\sqrt{2\\}[/tex]=b/a b/a is rational,but [tex]\sqrt{2\\}[/tex] is irrational which cotradicts our assumption ∴ 1/[tex]\sqrt{2\\}[/tex] is irrational Reply
1√2=ab Where a and b are co primes. Co-primes are the prime numbers which do not have a common root. So that we got 2 divides b2. Let b2=c where c in other numbers. Reply
Answer:
Step-by-step explanation:
assume that 1/[tex]\sqrt{2\\}[/tex] is rational
1/[tex]\sqrt{2\\}[/tex]=a/b,where a and b are integers
1/[tex]\sqrt{2\\}[/tex]=a/b
[tex]\sqrt{2\\}[/tex]/1=b/a
[tex]\sqrt{2\\}[/tex]=b/a
b/a is rational,but [tex]\sqrt{2\\}[/tex] is irrational
which cotradicts our assumption
∴ 1/[tex]\sqrt{2\\}[/tex] is irrational
1√2=ab Where a and b are co primes. Co-primes are the prime numbers which do not have a common root. So that we got 2 divides b2. Let b2=c where c in other numbers.