In a right triangle RQP if PQ=5cm RQ=10cm find the value of : (i) sin2P (ii) tan R (iii) sin P x cos P (iv) sin2P – cos2 P About the author Serenity
Step-by-step explanation: In △PQR, right angled at Q. If PQ=5 and RQ=10cm find sin 2 P. Medium share Share Answer PR 2 =PQ 2 +QR 2 PR 2 =25+100 PR 2 =125 PR= 125 =5 5 sin 2 P= PR 2 QR 2 = 125 100 = 5 4 solution Expand-image verified_toppr Answer verified by Toppr View 328 Views Reply
Step-by-step explanation:
In △PQR, right angled at Q. If PQ=5 and RQ=10cm find sin
2
P.
Medium
share
Share
Answer
PR
2
=PQ
2
+QR
2
PR
2
=25+100
PR
2
=125
PR=
125
=5
5
sin
2
P=
PR
2
QR
2
=
125
100
=
5
4
solution
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Answer verified by Toppr
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